(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A 7.0-g bullet is fired into a 1.5-kg ballistic pendulum. The bullet emerges from the block with a speed of 200 m/s, and the block rises to a maximum height of 12 cm. Find the initial speed of the bullet.

Now I think this is an imperfect inelastic collision because the bullet does not lodge itself in the pendulum. So I assumed since it was inelastic I could ignore conservation of kinetic Energy.

2. Relevant equations

Conservation of Momentum

Conservation of Energy

3. The attempt at a solution

m1v1i +m2v2i=(m1 + m2)vf

(.007kg x v1i)+0=(1.507kg)vf

(PE + KE)collision=(PE + KE)top

0 + (.5 x 1.507 x vf^2)= mgh + .5mv^2

0 + (.5 x 1.507kg x vf^2) = (1.5 kg x 9.81m/s^2 x .12m) + (.5 x .007kg x 200^2)

vf^2=(1.7658J + 140J)/(.7535kg)

vf=13.716m/s

(.007kg x v1i)=1.507kg x 13.716m/s

v1i = 2952 m/s

Now I know this is not the answer because the answer is given as 530m/s but I can't for the life of me figure out what went wrong with the energy calculation. (I'm assuming that's where the big boo boo happened)

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# Ballistic Pendulum

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