a 4.00g bullet moving at 380m/s embeds itself in a wood block of mass 2996g suspended as a ballistic pendulum find: (a)the initial velocity of the block after the impact, and (b) how high the block rises.(adsbygoogle = window.adsbygoogle || []).push({});

I did it this way can someone tell me if i did it right

(a)m(1)v(1i) + m(2)v(2i) = (m(1) +m(2))v(f)

m(1)v(1i)/(m(1)+m(2))=v(f)

(4.00*380)/(4.00+2996)=.5067m/s

(b) U+K=U(2) +K(2)

1/2 mv^2 = mgh

v^2/2g=h

.507^2/(2*9.80)=.0131m

Any Help would be appreciated

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# Homework Help: Ballistic pendulum

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