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Divers at Acapulco dive from a cliff that is 61m high. If the rocks below the cliff extend outward for 23m, what is the minimum horizontal velocity a diver must have to clear the rocks safely?

x problem

x=Vx(t)

23=Vx(t)

23=Vx(3.52)

23/3.52=Vx

Answer is Vx=6.52m/s

Y problem

Vy=0m/s

t=?

d=-61m

a=-9.8m/s/s

d=1/2a(txt)+Vi(t)

-61=-4.9(txt)

-61/-4.9=txt

12.44=txt

square root 12.44=txt Answer for Time is 3.52 Seconds