A 23 g bullet traveling 235 m/s penetrates a 3.8 kg block of wood and emerges cleanly at 195 m/s.
If the block is stationary on a frictionless surface when hit, how fast does it move after the bullet emerges?
(1) mv= (m+M)v'
momentum before= momentum after
(2) 1/2(m+M)v'^2 = (m+M)gh
The Attempt at a Solution
I attempted to solvethis using these two equations and I received an answer for 1.14 m/s and 230 m/s. I am having a lot of trouble even determining how to start this problem. I dont want a quick easy answer but I would like help working through it! Thank You!