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Ballistics related problem

  1. Jul 18, 2012 #1
    This is NOT a school work/homework, it's just a problem relate to my personal interest found on a ballastics book. And I already converted all units into SI units to make it simple.
    I tried but couldn't get to correct answer.
    Please not a is speed of sound, K2 is a constant with equation.
    The answer is 0.28 mil lower which is also 0.01575 degree lower.

    1. The problem statement, all variables and given/known data
    A U.S. 37-MM projectile is fired with a muzzle velocity of 2600ft's (792.48m/s). The projectile weighs 1.61 Ibm(0.73kg). Assuming K2 = 0.841[unitless] and using standard sea level met data(ρ=0.0751Ibm/ft^3 (1.2kg/m^3), a = 1120 ft/s (341.4m/s))
    If this weapon is used at an increased altitude and assuming the density and temperature of the atmosphere are ρ=0.06Ibm/ft^3 (0.98kg/m^3) and T=30F degree, how much higher or lower will the weapon have to be aimed to hit a target at 800 yards.

    2. Relevant equations
    Drag force: F = 1/2ρ*S*C*V^2
    S = πd^2/4 (d is diameter)
    Cd = ρS/2m * K2*a/Vx = k2/Vx
    Vx = Vx0*exp(-k2*t) .......t is time of flight ot any range x
    Vy = (Vy0+g/k2)exp(-k2*t)-g/k2
    t=x/Vx0 * ln(Vx0/Vx) / (1-Vx/Vx0)
    tan∅ = tan∅0 + gx/Vx0^2((1-Vx0/Vx)/(1-Vx/Vx0)) .......∠∅ is the angle of fall and ∠∅0 is the initial launch angle
    y = y0 + x*tan∅0 - (g*t^2/(2ln(Vx0/Vx)))

    3. The attempt at a solution

    I first assume the first firing is flat firing, so the initial launch angle is zero, after the increased altitude, i calculated the new k2 and then apply it into these two equations:
    Vx = Vx0*exp(-k2*t) .......t is time of flight ot any range x
    Vy = (Vy0+g/k2)exp(-k2*t)-g/k2
    I assume the muzzle velocity is Vx at the halfway of the range since Vy and halfway of range is zero, i then manipulate these two equations to a form of Vy0/Vx0, and the do a inverse tan to get the initial launch angle.
    but it doesn't work and i realized that muzzle velocity is not Vx at halfway since the moment the projectile went out, the velocity is changing. and i was stuck here
     
  2. jcsd
  3. Jul 19, 2012 #2
    I would seem to me that in order to determine a difference in initial elevation based on different altitudes, you should be writing the differential equation describing the projectile motion and numerically integrating it. The drag force is a function of projectile speed. The drag coefficient itself is also a function of speed to some extent. There is also a slight difference in the acceleration of gravity at different altitudes if that were to be included.
     
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