Compute to three significant figures the wavelength of the sixth line in the hydrogen Balmer series.
1 / lambda = R * ( 1/ n_final^2 - 1 / n_initial^2 )
R = Rydberg constant = 10973731.57 m^-1
lambda = wavelength
The Attempt at a Solution
I set up the Balmer formula I listed above given the info in the problem
1 / lambda = (10973731.57 m^-1) * ( 1/ 2^2 - 1 / 6^2 ) = 1 / 2438607.015555 m^-1
so, lambda = 410.070 nm
or 4.10 x 10^-7 m using 3 sig figs as the question asks for.
Not sure what I am doing wrong. This seems right to me, but it is not.
Any help is appreciated.