1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Banked curve problem

  1. Mar 5, 2006 #1
    [​IMG]

    theta = 21 degrees
    Mu = 0
    radius = 150 meters
    a = radial acceleration of uniform circular motion

    a = v^2 / r

    The sum of all forces = m*a

    Since the car is at an angle and Fn is always perpendicular I split it into X and Y components.

    Fn in the x direction = Fn sin theta
    Fn in the y direction = Fn cos theta

    X direction: Fn sin theta = m (v^2 / r)

    Y direction: no acceleration so Fn cos theta - Fg = 0
    Fn = (mg / cos theta)

    By substitution into the equation for the x direction:

    ( mg / cos theta ) * sin theta = m (v^2 / r)

    mg tan theta = m (v^2 / r)

    cancelling m and re-arranging...

    tan theta = ( v^2 / rg )

    v^2 = tan 21 / (150 * 9.8)
    v^2 = 564.28

    v = 23.75 meters per second


    Is this answer correct?
     
  2. jcsd
  3. Mar 5, 2006 #2

    Fermat

    User Avatar
    Homework Helper

    Yes.
    Your working is pefectly correct and the answer is correct.

    There's just a little typo. You used a '/'-sign instead of a '*'-sign between the tan21 and the 150*9.8
     
  4. Mar 5, 2006 #3
    Yes you are correct with the equations tan(theta) = v^2/rg.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Banked curve problem
  1. Banking curve problem (Replies: 1)

  2. Banked curve problem (Replies: 3)

  3. Banked Curve Problem (Replies: 6)

Loading...