# B Banked Curves

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1. Aug 3, 2016

### marlasca23

Why during a banked curve is the horizontal component of the normal force considered as the net force and the centripetal force? The horizontal component of Normal force, N·sinθ, is not even ponting towards the centre of the curvature.

2. Aug 3, 2016

### jbriggs444

It is pointing toward the center of curvature of the trajectory of the vehicle.

Edit: A geodesic on the surface would curve otherwise, but gravity affects the vehicle's path.

Last edited: Aug 3, 2016
3. Aug 3, 2016

### A.T.

Because the vertical component is cancelled by gravity.

4. Aug 3, 2016

### marlasca23

Sorry, I don't understand that. Could you explain it more in depth, please?

5. Aug 3, 2016

### jbriggs444

The vehicle travels in a circular path around the banked curve. The circle is in a horizontal plane. The center of the circle is in that plane. The net force on the vehicle is toward that center.

The "center of curvature" of a circular arc is the center of the circle containing that arc.

6. Aug 3, 2016

7. Aug 3, 2016

### marlasca23

Thanks! My confusion was because I thought that the center of the curve was supposed to be at ground level.Thanks again :)