- #1
MAPgirl23
- 65
- 0
A barrel contains a layer of oil of thickness 0.110 m floating on water of depth 0.245 m. The density of the oil is 630 kg/m^3
a) What is the gauge pressure at the oil-water interface?
b) What is the gauge pressure at the bottom of the barrel?
**
a) Atmospheric Pressure + Pressure caused by oil = Total Pressure at oil-water interface
Pressure caused by oil = density * depth * g
Pressure caused by oil = 630 kg/m^3 * 0.11 m * 9.81 = 679.14 Pa
Total Pressure = 101325 Pa + 679.14 Pa but still gives me the wrong answer
***The 101325 is atmospheric pressure which is exerted in addition to the pressure caused by the oil.
b) Pressure at bottom = Pressure at oil-water interface + pressure caused by water
Pressure caused by water = density * depth * g
Pressure caused by water =1000 * 0.245 m * 9.8 = 2401
P = 102004.833 Pa + 2401 Pa but still gives me the wrong answer
***The 102004.833 is the atmospheric pressure plus the pressure of the oil which is exerted on the bottom of the container in addition to the pressure caused by the water
Please help
a) What is the gauge pressure at the oil-water interface?
b) What is the gauge pressure at the bottom of the barrel?
**
a) Atmospheric Pressure + Pressure caused by oil = Total Pressure at oil-water interface
Pressure caused by oil = density * depth * g
Pressure caused by oil = 630 kg/m^3 * 0.11 m * 9.81 = 679.14 Pa
Total Pressure = 101325 Pa + 679.14 Pa but still gives me the wrong answer
***The 101325 is atmospheric pressure which is exerted in addition to the pressure caused by the oil.
b) Pressure at bottom = Pressure at oil-water interface + pressure caused by water
Pressure caused by water = density * depth * g
Pressure caused by water =1000 * 0.245 m * 9.8 = 2401
P = 102004.833 Pa + 2401 Pa but still gives me the wrong answer
***The 102004.833 is the atmospheric pressure plus the pressure of the oil which is exerted on the bottom of the container in addition to the pressure caused by the water
Please help