Baryon effective Lagrangian

  • Thread starter Andrea M.
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  • #1
Andrea M.
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I'm trying to understand how to construct effective lagrangians for the hadrons. I understand the procedure for the mesons but I get stuck on baryons. In particular I don't understand how the baryons should transform under a chiral transformation. I mean for the mesons it was easy because they could be interpreted as the Goldston bosons of the theory, but for baryons?

Thanks in advance for the answers.
 

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  • #2
fzero
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Are you working from a specific reference? In the linear sigma model, for example, the nucleon is introduced as a Dirac spinor. The chiral symmetry is manifest as ##SU(2)_L\times SU(2)_R##, where the factors act independently on the chiral components of the spinor.
 
  • #3
Andrea M.
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I'd like to understand how the octet of baryons ##B## transforms under ##SU(3)_L\times SU(3)_R##. The only thing I know is that it must transforms as the eight dimensional representation of the unbroken symmetry ##SU(3)_V## but I don't get why it should transform like
$$
B\to h(\phi,g)Bh^{\dagger}(\phi,g)
$$
where ##\phi## are Goldstone bosons fields, ##g## is a ##SU(3)_L\times SU(3)_R## transformation and ##h## is a ##SU(3)_V## transformation as claimed for example in Pich, A. & de Rafael, E., 1991. Strong CP violation in an effective chiral Lagrangian approach. Nucl. Phys., B367(2), pp.313–333.
 
  • #4
fzero
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I am not that familiar with specific nonlinear realizations, but there is a draft version of Georgi's book available at www.people.fas.harvard.edu/~hgeorgi/weak.pdf. This representation is discussed in Ch. 6, but you will need to refer to the discussion of mesons in Ch. 5 to figure out the notation.
 
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  • #5
Andrea M.
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Yes I've already read this but I still have some doubts, I will give him another chance.
 

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