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Basal metabolism problem

  1. Jan 31, 2006 #1
    I can't seem to get this problem to work out...any suggestions?

    -HOw much water would have to evaporate from the skin/min to take away all of the heat generated by basl metabolism (60kcal/hr) for a 65Kg person.
  2. jcsd
  3. Jan 31, 2006 #2


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    The heat generated by this process needs to change the water from its liquid to its vapor state. The amount of heat, [itex]Q[/itex], required to alter a mass [itex]m[/itex] of water to its vapor state is given by
    [tex]Q=mL[/tex] where [itex]L[/itex] is the heat of vaporization of water which is [itex]539\ kcal/kg[/itex].
  4. Jan 31, 2006 #3
    So would I set the problem up like this:

    60 Kcal/hr (60 min/hr)= m (539 Kcal/kg)

  5. Jan 31, 2006 #4


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    That is about seven liters of water per minute!
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