Baseball Problem - Determine Speed of Ball After Impact

[leezak]

A pitcher throws a 0.126-kg baseball, and it approaches the bat at a speed of 32.6 m/s. The bat does 71.7 J of work on the ball in hitting it. Ignoring air resistance, determine the speed of the ball after the ball leaves the bat and is 29.6 m above the point of impact.

i found that the initial KE is 310.36 and I'm not sure where to go from there can someone help? thanks!

 

[zack_21]

Break up the kinetic energy in order to get the initial velocity. Use the kinematic equations to solve the rest.

 

[tomcue]

I would approach this problem by using the principle of conservation of energy. We can assume that the initial kinetic energy (KE) of the ball is equal to the work done on it by the bat, which is 71.7 J. This means that the final KE of the ball after impact is also 71.7 J.

To determine the final speed of the ball, we can use the equation for kinetic energy: KE = 1/2 * m * v^2, where m is the mass of the ball and v is its final velocity.

Rearranging the equation, we get v = √(2 * KE / m). Plugging in the values given in the problem, we get v = √(2 * 71.7 J / 0.126 kg) = 30.19 m/s.

This is the final speed of the ball at 29.6 m above the point of impact, assuming no air resistance.