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Homework Help: Basic Algebra

  1. Dec 16, 2005 #1
    Can someone explain to me why E = .5(k/a)(e^2 - 1)/(1 - e^2) = .5(k/a)

    The conjugate won't work, how do I show this?
     
  2. jcsd
  3. Dec 16, 2005 #2
    You can factor -1 out of the denominator and then cancel (e^2-1), but that leaves you with E = .5(k/a)(e^2 - 1)/(1 - e^2) = -.5(k/a)

    GM
     
  4. Dec 16, 2005 #3
    Actually that was what I meant 0.5(k/a), thanks
     
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