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Basic Binomial Division

  1. Sep 18, 2011 #1
    1. The problem statement, all variables and given/known data

    (v-4)/(5v+1)

    3. The attempt at a solution

    I'm an engineering student, and I'm taking Differential Equations, but I can't remember how to do simple things like this.

    A walk through explanation would be very much appreciated, I don't have a lot of time to spare.

    The simplification I need to arrive at is = 1/5 - 21/(5*(5v+1))

    The solution I've come up with is 1/5 - 42/(5v+1)

    Can anyone help? Thanks
     
  2. jcsd
  3. Sep 18, 2011 #2

    symbolipoint

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    The process is fundamentally the same as ordinary base-ten division using expanded form.

    v vidided by 5v is 1/5. Multiply 1/5 by (5v+1), subtract from (v-4). Remainder is -4.2, but would be, "negative four and one fifth", in mixed number form.
    My result seems to be (1/5)-4&(1/5)/(5v+1).
    [itex]\frac{1}{5}-4\frac{1}{5}/(5v+1)[/itex], seems TeX is not working.
    [itex]\frac{}{}-\frac{}{}[/itex]
     
    Last edited: Sep 18, 2011
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