1. The problem statement, all variables and given/known data A slab of ice floats on a freshwater lake. What minimum volume must the slab have for a 73.4 kg person to be able to stand on it without getting his or her feet wet? (use 920kg/m^3 as density of ice and 1000 kg/m^3 for the density of freshwater) 2. Relevant equations Archimedes Principle: Fg = Fb mg = pVg 3. The attempt at a solution So my problem was I was really sick and I missed my couple first lectures on this topic. I've learned what I can from my textbook... but i think i'm missing a step or something in this problem. This is what I figured I should do: Since the buoyant force is equal to amount of liquid displaced, i plugged in the mass of the person and density of freshwater into Archimedes equation to solve for volume of water displaced. Vwater displaced = (73.4 kg) / (1000 kgm-3) Vwater displaced = 0.0734m3 Than from here, I really haven't worked with this subject for long enough to understand what i can and cannot do. My next attempt would be to solve for the volume of ice by doing: pwaterVwater displaced = piceVice Vice = pwaterVwater displaced / pice Vice = (1000kgm-3)(0.0734m3) / (920kgm-3) Vice = 0.0798 m3 Is this the correct answer? if not what should i have done?