(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

If sinx(lnx)=0 over [0, 2pi] then x=_____

3. The attempt at a solution

My attempt was to move sin over to the other side to get lnx= 0/sinx and then get lnx=0, making x=1. But is it incorrect to just move sinx over to the other side, because if i move lnx over to the other side, i would get x=0. Can you please explain to me what I am doing wrong here?

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# Homework Help: Basic Calculus- Please help

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