(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

If sinx(lnx)=0 over [0, 2pi] then x=_____

3. The attempt at a solution

My attempt was to move sin over to the other side to get lnx= 0/sinx and then get lnx=0, making x=1. But is it incorrect to just move sinx over to the other side, because if i move lnx over to the other side, i would get x=0. Can you please explain to me what I am doing wrong here?

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Basic Calculus- Please help

**Physics Forums | Science Articles, Homework Help, Discussion**