1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Basic Cicuit Analysis - Mesh

  1. Mar 26, 2006 #1
    This is a question from a review for our midterm coming up soon. I don't understand what I am doing wrong and need some guidance. It would be rather tedious for you (the reader) to view an ASCII circuit, so here is a scan of my work:

    http://static.flickr.com/46/118451767_63645eb724_b.jpg

    Sorry for the link to another page. I couldn't resize it to upload to physicsforums because I don't have software on this computer to do it. I PROMISE it is just my work.

    Thanks in advance.

    EDIT:I forgot to draw [itex]V_x [/itex] on the circuit diagram!!! It is supposed to be over [tex] R_{4k\Omega} [/tex] with the labeled [tex] + [/tex] and [tex] - [/tex] right next to the loop 2 label.
     
    Last edited: Mar 26, 2006
  2. jcsd
  3. Mar 26, 2006 #2
    By Ohm's Law, [tex]V_x = (I_2 - I_3) \times 4000[/tex], thus [tex]I_1 = I_2-I_3[/tex], and not [tex]I_3-I_2[/tex] as you have written.
     
  4. Mar 26, 2006 #3
    Yeah, I get ohms law, and that the voltage for Vx is a combination of I1 and I2 multiplied by the resistance. I don't understand WHY it is:

    [tex] I1 = I2-I3 [/tex]

    and not: [tex] I1= I3-I2 [/tex]

    oh *shoot*... nevermind I got it now.

    The current is going to run from the high potential to the low potential, from positive to negative. If the current is running from positive to negative then the current that runs along side it is a POSTIVE I2 and a NEGATIVE I3.

    For some reason I was thinking that the current should run from negative to positive.


    cool. thanks.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Basic Cicuit Analysis - Mesh
  1. Cicuit analysis (Replies: 1)

  2. Basic Diode Analysis (Replies: 10)

Loading...