1. The problem statement, all variables and given/known data Please view the attached image. 2. Relevant equations P = VI = I^2 R = V^2 / R V = IR KVL 3. The attempt at a solution I'm having trouble with part A. I got part B. My Part A Problem: I chose my reference direction of I to be going clockwise (to satisfy passive sign convention). Now, since P is positive (which denotes absorption), we know that I = .25mA. How? P = IV... 2.5mW = 10V * I. Knowing that, I found Vx by using Ohm's law. V = IR Vx = -.25mA * 10v = -2.5V Knowing that, to compute Vba, what I did was start from point B, go towards pt A. So... Vx + RI + 2Vx = Vba (-2.5V) + (3kOhm)(-.25mA) + 2(-2.5) = Vba = -8.25 V How I solved part B: I think I got lucky here, cause what I did previously is this: P = VI = 2Vx * I = 2 (2.5) * .25mA... Notice it's + * + = +.. whereas it could be - * - = +, so my online HW told me it was right. However, now i'm skeptical about the sign of my amp when computing Vba. However, when I recalculated my current (I forgot to negate it while goign CCW), I come out with a negative current. So, I'm curious, is my Vba answer correct?