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Basic Circuit analysis

  1. Oct 10, 2004 #1
    ok the question I have is why is the voltage between the 220 olm resistor and the 330 olm resistor 0 V.

    All resistors in the image are in series so Is=I1=I2=I3

    Is = 10/1020 (v/olm) = .0098 or 9.8 mA

    V(subscript220)= 220*9.8 mA = 2.157 V (this is the voltage between the DC source and the 220 olm resistor)

    V(subscript330) = 330 * 9.8 mA = 3.234 V (this is the voltage between the 330 olm and the 470 olm resistor)

    V(subscript470) = 470 * 9.8 mA = 4.606 ( I have to add 3.234 to 4.606 to find the voltage between the DC source and 470 which is 7.84 V)

    I am taking the ground up above the the 330 olm resistor.

    Ok now I am not sure but I think the reason why the voltage across the 220 to the 330 olm resistor is zero is because I have to make a open circuit in that area which means that no current is actually passing through the wire since current takes the path of least resistence.
     

    Attached Files:

  2. jcsd
  3. Oct 23, 2004 #2
    ok the question I have is why is the voltage between the 220 olm resistor and the 330 olm resistor 0 V.
    be careful how you word your question!
    the answer to this question is that you are measuring the voltage on a 0 ohm conductor between r220 & r330
     
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