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Basic Conservation of Energy

  1. Oct 7, 2013 #1
    1. The problem statement, all variables and given/known data

    A 2-kg block is attached to a horizonal ideal spring with a spring constant of 200N/m. When the spring has its equilibrium length the block is given a speed of 5m/s. What is the maximum elongation of the spring.

    2. Relevant equations

    Conservation of mechanical energy, PEspring=0.5kx^2 KE=0.5mv^2

    3. The attempt at a solution

    It seems like a fairly simple question to me, applying conservation of mechanical energy at equilibrium and at maximum elongation we get 0 + 0.5kx^2 = 0 + 0.5mv^2, so x =√(mv^2/k) = 0.5 meters, however the solution says the answer should be 5 meters, can anyone tell me what I'm missing here?
     
  2. jcsd
  3. Oct 7, 2013 #2

    gneill

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    Staff: Mentor

    Your result looks good. Maybe a typo in the question? Perhaps they meant for the initial velocity to be 50 m/s.
     
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