- #1
FlO-rida
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i am looking for a simple definition of discontinuity using the example 3/(x^2+x-6)
at x=2,-3. i understand that but when you say x=a what do u mean by that. can you show me a variable formula (using a, b and c) that would better explain this
so you are saying that a would be the constant. like in my example if we factor x^2+x-6 we get (x-2)(x+3), so how would that be undefined
sorry but i still don't get it, its not like we have a denominator of zero
wat i ment was it dosent cancel out or anything
ok then how would you compare that with a function that is not discontinuous like 1/(x+3)
sorry but i still don't get it, its not like we have a denominator of zero
Say your function was
f(x)=1/(x-a)
Wouldn't you agree that [itex]\lim_{x \rightarrow a} = \infty[/itex] and so f(a) is undefined?
cancel out with what?
f(x)=1/(x+3) is discontinuous at x=3.