- #1

- 15

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I am stuck on a specific part of an equation, the equation is as follows;

Simplify (x^1/2 +1) (x^2 - x -2) (x -2)^-1

I am basically stuck on the last part (x -2)^-1, how would I go about simplifying this.

Help would be appriciated

Dominic

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- Thread starter Dragonetti
- Start date

- #1

- 15

- 0

I am stuck on a specific part of an equation, the equation is as follows;

Simplify (x^1/2 +1) (x^2 - x -2) (x -2)^-1

I am basically stuck on the last part (x -2)^-1, how would I go about simplifying this.

Help would be appriciated

Dominic

- #2

phyzguy

Science Advisor

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- 1,993

Try factoring the (x^2-x-2) term.

- #3

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- #4

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X/(2+1) * (x^2 - x -2) * 1/(x-2)

Factor this ^

x/3 * (x+1) * (x-2) * 1/(x-2)

You can then cancel out the x-2, and you're left with

(x/3) * (x+1) * 1

(x^2 + x) / 3

That's as simple as I could get it.

- #5

Mark44

Mentor

- 36,031

- 7,961

This is NOT an equation. An equation always has an = symbol.Hi,

I am stuck on a specific part of an equation, the equation is as follows;

Simplify (x^1/2 +1) (x^2 - x -2) (x -2)^-1

You need a pair of parentheses around the exponent. I believe you mean x^(1/2). Omitting the parentheses has confused one of the people responding to this thread.

I think that what you're asking about is this:

[tex](\sqrt{x} + 1)\frac{x^2 - x - 2}{x - 2}[/tex]

As already suggested, factor the x

I am basically stuck on the last part (x -2)^-1, how would I go about simplifying this.

Help would be appriciated

Dominic

- #6

- 15

- 0

This is NOT an equation. An equation always has an = symbol.

You need a pair of parentheses around the exponent. I believe you mean x^(1/2). Omitting the parentheses has confused one of the people responding to this thread.

I think that what you're asking about is this:

[tex](\sqrt{x} + 1)\frac{x^2 - x - 2}{x - 2}[/tex]

As already suggested, factor the x^{2}- x - 2 expression.

Thanks for the help,

Dominic

- #7

- 15

- 0

X/(2+1) * (x^2 - x -2) * 1/(x-2)

Factor this ^

x/3 * (x+1) * (x-2) * 1/(x-2)

You can then cancel out the x-2, and you're left with

(x/3) * (x+1) * 1

(x^2 + x) / 3

That's as simple as I could get it.

Thanks

Very helpful

Dominic

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