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Basic Equation Stuck?

  • Thread starter Dragonetti
  • Start date
  • #1
15
0
Hi,
I am stuck on a specific part of an equation, the equation is as follows;

Simplify (x^1/2 +1) (x^2 - x -2) (x -2)^-1

I am basically stuck on the last part (x -2)^-1, how would I go about simplifying this.

Help would be appriciated
Dominic
 

Answers and Replies

  • #2
phyzguy
Science Advisor
4,372
1,352
Try factoring the (x^2-x-2) term.
 
  • #3
I'm not sure exactly how simple you want it, do you want to remove variables from the bottom or are you okay with setting restrictions? You changed (x-2)^2 to 1/x-2 that's always a start then you can divide x-2 into something later HINT HINT.
 
  • #4
Here's what I came up with

X/(2+1) * (x^2 - x -2) * 1/(x-2)
Factor this ^

x/3 * (x+1) * (x-2) * 1/(x-2)
You can then cancel out the x-2, and you're left with

(x/3) * (x+1) * 1

(x^2 + x) / 3

That's as simple as I could get it.
 
  • #5
33,171
4,858
Hi,
I am stuck on a specific part of an equation, the equation is as follows;

Simplify (x^1/2 +1) (x^2 - x -2) (x -2)^-1
This is NOT an equation. An equation always has an = symbol.

You need a pair of parentheses around the exponent. I believe you mean x^(1/2). Omitting the parentheses has confused one of the people responding to this thread.

I think that what you're asking about is this:
[tex](\sqrt{x} + 1)\frac{x^2 - x - 2}{x - 2}[/tex]

As already suggested, factor the x2 - x - 2 expression.


I am basically stuck on the last part (x -2)^-1, how would I go about simplifying this.

Help would be appriciated
Dominic
 
  • #6
15
0
This is NOT an equation. An equation always has an = symbol.

You need a pair of parentheses around the exponent. I believe you mean x^(1/2). Omitting the parentheses has confused one of the people responding to this thread.

I think that what you're asking about is this:
[tex](\sqrt{x} + 1)\frac{x^2 - x - 2}{x - 2}[/tex]

As already suggested, factor the x2 - x - 2 expression.
Thanks for the help,
Dominic
 
  • #7
15
0
Here's what I came up with

X/(2+1) * (x^2 - x -2) * 1/(x-2)
Factor this ^

x/3 * (x+1) * (x-2) * 1/(x-2)
You can then cancel out the x-2, and you're left with

(x/3) * (x+1) * 1

(x^2 + x) / 3

That's as simple as I could get it.
Thanks
Very helpful
Dominic
 

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