A uniform bar of mass m is being moved on a smooth horizontal plane by applying a constant horizontal force F acting at the lowest point. If the rod translates making a constant angle 'theta' with vertical, the value of F must be?
2) Torque=Moment of Inertia X Angular acceleration
The Attempt at a Solution
I tried to equate net torque about center of rod and lowest point of rod to zero but can't figure out how to do so in either configuration, I figured the torque of the force about the center is F(L/2)cos(theta) assuming length of rod as L, I don't know how to proceed or how this will give us the value of F in terms of m, g and theta