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Basic FrictionIs this right?

  1. Aug 23, 2010 #1
    1. The problem statement, all variables and given/known data

    A load of 200kg rests on a horizontal plane.A horizontal force of 196N is needed to overcome friction.Find the coefficient of friction

    2. Relevant equations
    F(gravity)=W=mg
    F(friction)= (mu)N


    3. The attempt at a solution

    W=mg
    W=200(9.8)=1960N
    This then is the F(normal) also.

    Now
    F(fric)=(mu)N
    196=(mu)1960
    mu=196/1960=0.2=answer

    thanks in advance
     
  2. jcsd
  3. Aug 23, 2010 #2
    Looks good.
     
  4. Aug 23, 2010 #3
    looks good... except for the part 196/1960 = ... well not .2 XD
     
  5. Aug 23, 2010 #4
    Oops >.<
     
  6. Aug 24, 2010 #5
    Thanks for all the help.Yes, it was a typo....i know it should be 0.1 :)
     
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