1. The problem statement, all variables and given/known data Determine whether the series is convergent or divergent. Find the sum if possible Ʃ 1+2^n / 3^n n=1 -> infinity 2. Relevant equations a/1-r 3. The attempt at a solution I split it up so that the equation is now: Ʃ (1/3^n) + (2/3)^n n=1 -> infinity Ʃ (1/3^n) + Ʃ (2/3)^n n=1 -> infinity I know that it is convergent in the second term because 2/3 < 1, how do I setup a/1-r for term 1? :S a1=1/3 a1 = 2/3 (1/3)/(1-(1/3)) + (2/3)/(1-(2/3)) =5/2 The answer should be 3/2 on the answer sheet it says ?