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## Homework Statement

Mike jumps off a springy diving board located 10.0m above the surface of a swimming pool on the moon. He launches straight up at 15.0 m/s. (assume he misses the diving board on the way back down.) If g

_{moon}is exactly one-sixth g

_{earth}, at what time does he hit the water?

## Homework Equations

I used, x=x

_{0}+v

_{0}t+1/2at

^{2}, but my answers didn't work when I plugged them back in, I think my math may be way off or something.

## The Attempt at a Solution

0=10+(15)t+(1/2)(-9.80/6)t

^{2}

0=10+15t-(9.80/12)t

^{2}

-10=t(15-(9.80/12)t)

t= -10, 30.61

It can't be -10, but when I plug both of them back in to the original equation, it never works out.

Thanks in advance for any help!

-Tom