Hello,(adsbygoogle = window.adsbygoogle || []).push({});

I am having an issue with this simple kinematics problem. I have the question visualized, well, at least I think I do. Here is the question:

Two cars are traveling along a straight road. Car A maintains a constand speed of 80 km/h; car B maintains a constant speed of 110 km/h. Att= 0, car B is 45 km behind car A. How much farther will car A travel before it is overtaken by car B?

So to start off, I graphed the problem and came up with this:

http://album6.snapandshare.com/3936/45466/853951.jpg [Broken]

where series 1 is car A and series 2 is car B.

I also know that this has to do with position and time, so I am most likely going to use one of my kinematical equations that deals with position and time, so I chose the equation: [tex]x_{f}=x_{i}+v_{0}t+\frac{1}{2} a t^2[/tex] because I know that the accelleration is constant and is equal to 0 since the cars are not speeding up. I also know that the final positions have to be equal, but how do I equate the final positions of the two cars? Or is this even the right direction for me to solve the problem?

I mean, I could just graph the two lines, find the equations, and then find the intersection of those two lines, but I would like to learn how to do it using the kinematical equations.

Thanks

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Basic Kinematics Question

**Physics Forums | Science Articles, Homework Help, Discussion**