How Much Force Is Needed to Move a 1960 N Block of Dry Ice?

[Ahmad786]

16. A block of dry ice weighing 1960 N is lying on a walkway. The coeffi cient of friction of
the walking surface is 0.125. With what force must you push or pull the block to move it?
A. 1.57 x 104 N
B. 1960 N
C. 245 N
D. 6.38 x 10-5 N
(For this I multiplyed 1960N (which is the Fn or fg) by the coefficient of friction on the walking surface which is 0.125)
Is this correct?

 

[CompuChip]

The answer is correct.
The force [question: should you take gravitational or normal force here? e.g. on an inclined surface, these are not equal] multiplied by coefficient of friction gives the maximal frictional force. To get the block moving, you should exert at least this force [question: which physical law tells you that?].

 

[kerimek]

Your calculation is correct. To move the block of dry ice, a force of 245 N is needed. This is because the force of friction, which is equal to the coefficient of friction multiplied by the normal force (in this case, the weight of the block), must be overcome in order for the block to move. Therefore, the force needed to move the block is equal to the frictional force, which is 0.125 multiplied by 1960 N. This results in a force of 245 N.