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Basic newtons second law plus friction

  1. Oct 20, 2009 #1
    1. The problem statement, all variables and given/known data

    A person pushes horizontally with a force of 220 N on a 50 kg crate to move it across a level floor. The coefficient of kinetic friction is 0.25.

    (a) What is the magnitude of the frictional force?

    (b) What is the magnitude of the crate's acceleration?

    2. Relevant equations

    µmg
    F = ma
    F = µma
    F = Applied force - Frictional Force

    3. The attempt at a solution

    (a) What is the magnitude of the frictional force?

    (0.25) * (50) * (9.8) = 122.5


    (b) What is the magnitude of the crate's acceleration?

    F = 220-122.5 = 97.5N

    (97.5 / 50) = 1.95m/s^2

    Edit: Nevermind, it was correct all along.
     
    Last edited: Oct 20, 2009
  2. jcsd
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