you said i left out the vertical displacement at time, so that would be y in the case of this equation y = y0 + v0y*t - 1/2*g*t^2 , and y is 53 m ?
Right... the vertical component of the velocity will be zero.kara said:So i know that its v will be 0 m/s at max heigh.
That's right. You are looking for the value of x when y is maximum. Hint: When does it reach the maximum height?kara said:and b/c im looking for how far its been displaced horizontally from the launch pt. i am looking for x?
You left out part of that equation; it should be:kara said:i plugged in all my values but get stuck at one point with a negative square root:
53 = -1/2(9.8)t^2