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Basic Physics Question

  1. Nov 4, 2007 #1
    1. The problem statement, all variables and given/known data
    A winch at the top of a 15 meter tall building pulls a pipe of length 15 meters. The winch pulls the rope in at the rate of -0.3 m/s. Find the rate of vertical change and the rate of horizontal change at the upper end of the pipe when y = 6 meters.


    2. Relevant equations
    x^2 + y^2 = s^2
    x dx/dt + y dy/dt = s ds/dt

    3. The attempt at a solution

    The question is what is dx/dt and what is dy/dt. So I need two equations to relate the two.
    I have about two pages full in my notebook, it's probably better that I not share them?
     
  2. jcsd
  3. Nov 4, 2007 #2

    Astronuc

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    Staff: Mentor

    So basically, the pipe starts horizontally and is then rotated to be vertical?

    The rope is always pulling at velocity with magnitude v = 0.3 m/s, and one has to resolve the rope velocity into vertical and horizontal components.
     
  4. Nov 4, 2007 #3
    Thank You!!!
     
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