- #1

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5% of students on a school bus are not enrolled in sports. If there are 500 students on a bus. What is the expected numbers of students who are not enrolled in sports on any given bus?

So, 5%(500)=25??

is this correct? Thanks

- Thread starter BCCB
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- #1

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5% of students on a school bus are not enrolled in sports. If there are 500 students on a bus. What is the expected numbers of students who are not enrolled in sports on any given bus?

So, 5%(500)=25??

is this correct? Thanks

- #2

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That's one hell of a big bus ! Yes, the math looks correct.

- #3

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would the solution change at all if it were worded as "5% of students all students are not enrolled in sports"...?

thanks

- #4

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I don't understand that wording at all so have no idea what it means.

would the solution change at all if it were worded as "5% of students all students are not enrolled in sports"...?

thanks

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- #6

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Why would you expect this to give a different answer than your original wording? If you were asking about students NOT on the bus, the answers might be different, but this looks the same.5% of all students are not enrolled in sports. If there are 500 students on a bus. What is the expected numbers of students who are not enrolled in sports on any given bus?

- #7

statdad

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In the first case nothing is random: you are told the number of students on a bus, and told that 5% of them do not play sports. In this case you know that 500 times 5%, or 25, of the students are not in sports.

If I understand your second version, you are told that 5% of all students at the school do not play sports, and then are asking how many of the 500 on the bus

The difference is in interpretation: in the first posing we KNOW the number is 25, the second is the number in an expected value.

- #8

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thanks for the clarification, I understand it now

- #9

HallsofIvy

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But as I drive to work to day, I **will** keep an eye out for that 500 passenger bus!

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