# Basic Projectile Motion question.

1. Sep 19, 2007

### scorpion990

Galileo throws a rock from the top of the Leaning Tower of Pisa at an upward angle of 60 degrees with speed v. The rock is in flight for 6.5 seconds and hits the ground 15 m from the base of the building. Ignore air resistance and ignore the fact that the tower tilts a bit. a. What is the speed v? b. How high off the ground is the top of the tower?

This is what I did the first time:
R = v^2*sin(theta)/g (Formula for range)
15 = v^2*sin(60)/9.8
v is approximately 13.028468 m/s
vy = 13.028468sin60 = 11.2829843 m/s
I then used the fact that ay = -9.8 m/s^2 and integration to make a model for position. I set it equal to 0, and I got that the height of the building equals 133 m. However, the real height is about 50 m, so I know I'm doing something incorrectly =/

I just realized that my logic is flawed. The "range" is defined as the distance in the x direction traveled where the starting and ending heights are the same. Mine are not, so I can't use the range formula. However, I can't imagine how else I can solve this. Can anybody point me in the right direction? Thanks.

2. Sep 20, 2007

### andrevdh

The horizontal speed of the rock is constant and it is the x-component of the initial speed, v, of the rock.

3. Sep 20, 2007

### tony873004

Start by computing the x-component of the speed. Like andrevdh says, its consistent. So it's no different than asking "how fast do I need to go to cover 15 meters in 6.5 seconds?" The easy way to think of this is the speedometer on your car. If you are travelling 60 miles per hour, that's 60/1, which is your distance divided by your time. So velocity is distance / time. 60 miles in 2 hours = 60/2 or 30 mph.

Once you know your velocity's x-component (15m/6.5s), and your angle (60 deg), draw a triangle, use some trig, and compute the other leg of the triangle. It represents your velocity's y-component.

Also avoid doing stuff like this: 15 = v^2*sin(60)/9.8
Don't start plugging numbers into your formulas until you have isolated your unknown variable to the left of the equal sign. Assuming this is the formula you would want to use:

R=v^2*sin(theta)/g
v^2=R/(sin(theta)/g)
v=sqrt(R/(sin(theta)/g))

v=sqrt(15/sin(60)/9.8))

It's not wrong to do it your way, but it leads to more errors because you're manipulating numbers instead of variables.

I forget what the range formula is, but are you sure that's it? your x-component would be cos(60) or 1/2 of this speed, and something travelling 6.5 m/s for 6.5 seconds is going to go a lot farther than 15 meters.

Does your teacher really want you to use calculus to solve this problem? It's not necessary.

I think your teacher is fudging the numbers here. The real Tower of Pisa is 55 meters tall. Like you, I get an answer a lot higher than that (but not equal to your answer).

Last edited: Sep 20, 2007
4. Sep 20, 2007

### capnahab

Being an old Fire Control Technician, the speed of gravity is 32 feet per second per second in a vacuum at sea level. Just do the math.

5. Sep 20, 2007

### Staff: Mentor

That would be the acceleration of gravity, not the speed.

EDIT -- Oh, and the acceleration of gravity does not depend on whether there is a vacuum or not.

Last edited: Sep 20, 2007
6. Sep 20, 2007

### scorpion990

I still can't seem to solve it =/
I get
Vx = 2.31 m/s
Vy = 4.00 m/s

Py = -4.9t^2 + 4t + H
Plugging in Py = 0 and t = 6.5 yields a much higher H than 50 m =/ Errrrrrr....

7. Sep 20, 2007

### msimmons

It looks like you did it right, is 50m a given answer or for example just a fact

Last edited: Sep 20, 2007
8. Sep 20, 2007

### tony873004

I got a much higher answer too. What answer did you get? What makes you think the answer is 50? Is it in the back of the book, or did you Google for Leaning Tower of Pisa and get the answer there?

9. Sep 20, 2007

### scorpion990

I got ABOUT 180 meters. I don't remember the exact answer. I googled it, and it said H = 50 meters =/

I think I'm just being overly paranoid about getting it correct.

10. Sep 20, 2007

### tony873004

I got 181 meters. Don't trust that the author of the book knows how tall the Tower of Pisa is.