- #1
syang9
- 61
- 0
alright, i know this is really basic stuff, so please bear with me.
let's say i have a box or something that is sliding horizontally at 2m/s across a table. all of a sudden it falls 0.5m to the ground. what's the speed of the box right before it hits the floor?
okay, so it's pretty easy to see that 0.5m will result in a vertical velocity component of sqrt(10) m/s. my question is, to get the speed, do i just add them up in quadrature? i.e.,
speed = sqrt(2^2 + sqrt(10)^2) = sqrt(14)?
let's say i have a box or something that is sliding horizontally at 2m/s across a table. all of a sudden it falls 0.5m to the ground. what's the speed of the box right before it hits the floor?
okay, so it's pretty easy to see that 0.5m will result in a vertical velocity component of sqrt(10) m/s. my question is, to get the speed, do i just add them up in quadrature? i.e.,
speed = sqrt(2^2 + sqrt(10)^2) = sqrt(14)?