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Basic question on ring and unities

  1. Aug 19, 2014 #1
    Z = field of integers

    .

    If R is a ring and k is an element of Z, write kR = {kr | r is an element of R}. It is not too difficult to verify that {k is an element of Z | kR = 0} is an additive subgroup of Z.

    I am confused on how kR would equal 0? Wouldn't that mean that k would have to equal zero? How could all of the elements of R multiplied by some integer k ever equal 0?

    The book goes on to say that kR = 0 if and only if k1 = 0, where 1 = the unity of R.

    Anyone want to help me understand what's going on here?
     
  2. jcsd
  3. Aug 19, 2014 #2

    Erland

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    Take Zk, the ring of integers modulo k, where k is a positive integer. Clearly, kr (that is, r+r+...+r, k times) equals 0 in Zk, for any r in Zk, right?
     
  4. Aug 19, 2014 #3
    Oh, thank you! So the complex plane, real numbers, integers all have char R = 0?
     
  5. Aug 19, 2014 #4

    Erland

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    Yes.
     
  6. Aug 30, 2014 #5

    WWGD

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    Quick comment and a nitpick ; nitpick , re post #1 ,is that the integers are not a field, they are a ring. As a general comment notice that you may have non-trivial torsion in infinite algebraic structures.
     
  7. Sep 3, 2014 #6
    The ring ℤ of integer numbers isn’t a field. Skipped all after such introduction.
     
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