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Basic Special Relativity Problem

  1. Oct 3, 2011 #1
    1. The problem statement, all variables and given/known data

    The Concorde traveled 8000 km between 2 places in North American and Europe at an average speed of 375 m/s. What is the total difference in time between 2 similar atomic clocks, one on the airplane and one at rest on Earth during a one-way trip? Consider only time dilation and ignore other effects like Earth's rotation.

    2. Relevant equations

    Δt_E = γ(Δt_S), γ = [1-(v/c)^2]^.5

    3. The attempt at a solution

    Here's my thinking: I can find the elapsed time during a one-way trip as measured from Earth frame by dividing the distance (8000 km) by the speed (375 m/s). Then, since the airplane and its clock are moving relative to Earth, the elapsed time interval will be smaller as measured from Earth frame. So I use the equation above.

    The problem is that v/c is WAY too small even for a scientific calculator, which just treats it as zero. What can I do with this problem? I tried a binomial approximation, but that didn't help much.
  2. jcsd
  3. Oct 3, 2011 #2

    Ray Vickson

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    Gamma is approx 1 -(.5)*(v/c)^2, where v = 3.75*10^2 and c = 3*10^8, so you can get v/c = f*10^(-6), and can easily get f using you calculator. This is the type of thing we used to do on a sliderule, way back in the Stone Age.

    Last edited: Oct 3, 2011
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