Why Do Different Electron Transitions Emit Different Spectral Lines?

In summary, the emission spectrum of an unknown element contains two lines - one in the visible portion of the spectrum and the other in the ultraviolet, due to differences in energy. This can be explained by the inverse relationship between energy and wavelength, where the ultraviolet line has a shorter wavelength and therefore more energy. Additionally, according to Neil Bohr's model of the atom, electron transitions that occur farther from the nucleus emit more energy than those closer to the nucleus, leading to the ultraviolet line being produced by a transition between energy levels farther from the nucleus. For more information on this topic, you can refer to the Rydberg formula.
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The emission spectrum of an unknown element contains two lines - one in the visible portion of the spectrum, and the other, ultraviolet. Based on the electromagnetic spectrum and Neil Bohr's model of the atom, account for the difference in energy between these two lines.

I'm having a bit of a difficult time understanding exactly why different elements emit electromagnetic waves as they decrease in energy. Anyways, my answer looks something like this so far...

The energy of a particle increases as the inverse of its wavelength. Due to the fact that ultraviolet light has a lesser wavelength than visible light, the line that is within the ultraviolet portion of the spectrum will have more energy. Also, electron transitions that occur farther away from the nucleus will emit more energy than those that occur closer to the nucleus. Thus, the electron transition that was responsible for producing the ultraviolet light must have occurred between two energy levels that were farther from the nucleus than the electron transition that was responsible for emitting visible light.

This is honestly the best I could come up with, and I know my terminology could use a lot of work, too. Any suggestions on how to improve this so I can get the full 3 marks? Any help would be much appreciated!
 
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1. What is spectroscopy?

Spectroscopy is the study of the interaction between matter and electromagnetic radiation. It involves the measurement and analysis of the different wavelengths of light absorbed, emitted, or scattered by a substance, which can provide information about its composition, structure, and physical properties.

2. What are the basic principles of spectroscopy?

The basic principles of spectroscopy involve the absorption, emission, or scattering of light by a substance. This interaction depends on the energy levels of the atoms or molecules in the substance, which are unique to each element or compound. By analyzing the wavelengths of light involved, we can determine the composition and properties of the substance.

3. What are the different types of spectroscopy?

There are several types of spectroscopy, including UV-Visible, Infrared, Nuclear Magnetic Resonance (NMR), and Mass Spectrometry, among others. Each type uses a different range of wavelengths and techniques to analyze the sample, and each has its own advantages and limitations.

4. How is spectroscopy used in scientific research?

Spectroscopy is used in a wide range of scientific research fields, including chemistry, physics, astronomy, and biology. It allows scientists to identify and characterize substances, study their chemical and physical properties, and understand their behavior and interactions with other substances. Spectroscopy is also used in environmental analysis, medical diagnostics, and forensics.

5. What are some real-world applications of spectroscopy?

Spectroscopy has many practical applications, such as analyzing the composition of food, detecting pollutants in the environment, and identifying the chemical makeup of unknown substances. It is also used in industries such as pharmaceuticals, agriculture, and materials science to ensure quality control and develop new products. In astronomy, spectroscopy is used to study the composition and movement of stars and galaxies in the universe.

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