• Support PF! Buy your school textbooks, materials and every day products via PF Here!

Basic Statistical Measures

  • Thread starter chrisyuen
  • Start date
1. Homework Statement

The pass mark of an examination is set at 40. The following table shows some summary statistics of the marks (x) of the 200 students who took the examination.

Mark Range: x >= 40, x < 40
Number of students: 160, 40
Mean: 64.0, 32.0
Standard deviation: 6.0, 4.0

The teacher wants to scale the marks so that more students will pass the examination. The new mark corresponding to x is

y = 50 + [tex]\frac{5}{6}[/tex](x - 40), if x >= 40
y = [tex]\frac{5x}{4}[/tex] if x < 40

(a) Find the mean and standard deviation of the new marks of the 200 students.
(b) The median of the original 200 marks is 52. Find the median of the new marks.

(Answer:
(a) 64; 13
(b) 60)

2. Homework Equations

Basic Formulae for Statistical Measures

3. The Attempt at a Solution

I don't know how to find the standard deviation for part (a) and the median for part (b).

Can anyone tell me how to solve them?

Thank you very much!
 
Last edited:
I know that part (b) can be solved using linear transformation y = ax + b.

50 + [tex]\frac{5}{6}[/tex](52 - 40) = 60 but not [tex]\frac{5(52)}{4}[/tex].

Can anyone tell me the reason?

Thank you very much!
 
Last edited:

Related Threads for: Basic Statistical Measures

  • Posted
Replies
4
Views
4K
  • Posted
Replies
1
Views
2K
  • Posted
Replies
1
Views
983
  • Posted
Replies
0
Views
924
Replies
12
Views
4K

Physics Forums Values

We Value Quality
• Topics based on mainstream science
• Proper English grammar and spelling
We Value Civility
• Positive and compassionate attitudes
• Patience while debating
We Value Productivity
• Disciplined to remain on-topic
• Recognition of own weaknesses
• Solo and co-op problem solving
Top