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Basic topology proof

  • Thread starter bedi
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  • #1
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Homework Statement



Let E be a nonempty set of real numbers which is bounded above. Let y=sup E. Then y [itex]\in[/itex] E closure. Hence y [itex]\in[/itex] E if E is closed.


Homework Equations



E closure = E' [itex]\cup[/itex] E where E' is the set of all limit points of E.

The Attempt at a Solution



By the definition of closure, y is either in E' or E (maybe in both). If E is closed, E' [itex]\subset[/itex] E and we know that the union of a set and its subset is the set itself. Therefore E closure = E.

Is this a valid proof?
 

Answers and Replies

  • #2
938
9
Shouldn't you be proving that if y=sup(E), then y ∈ E closure?
 

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