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Basics and brainlock

  1. Oct 30, 2005 #1
    (100) (.2)x(.8) 100-x
    Trying to solve this using 1, then 2 for x. The same parentheses are around both the 100 and the x.
  2. jcsd
  3. Oct 30, 2005 #2


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    Do you mean that first term, in which "The same parentheses are around both the 100 and the x" is a fraction: (100/x) or the binomial coefficient?

    Oh, yes, of course, that's a "binomial distribution" calculation:
    [tex]\frac{100!}{x!(100-x)!}.2^x .8^{(100-x)}[/tex]

    With x= 1 that is
    All except the last term are easy. You may want to use a calculator for .899!

    With x= 2 that is

    Do the arithmetic! (Cancel a lot in those binomial coefficients first.)
    Last edited: Oct 30, 2005
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