# Basics Physics Need Help

• calcium12
In summary, the problem involves a stunt man running horizontally off a cliff at a speed of 6.0 m/s and landing in a river 23m below the cliff. The questions ask for the time, horizontal and vertical components of the stunt man's speed, his overall speed, the angle at which he hits the water, and the distance from the base of the cliff to the point of impact. The equations V1y=V1sin(theta) and V1x=V1cos(theta) can be used, along with the equation D=(V2)(t)-0.5(a)(t^2) to find the solutions. However

#### calcium12

Basics Physics...Need Help

## Homework Statement

-In a movie, a stunt man runs horizontally off a cliff at a speed of 6.0 m/s. The stunt man lands in a deep river that is 23m below the cliff.

A) Determine when the stunt man lands in the river.

B) Determine the horizontal component of the stunt man's speed as he hits the river.

C) Determine the vertical component of the stunt man's speed as he hits the river.

D) Determine the stunt man's speed as he hits the river.

E) Determine the angle he hits the water at.

F) How far from the base of the cliff does the stunt man hit the water ?

## Homework Equations

V1y=v1sin (feta=angle)

V1x=V1cos (feta)

D=(V2)(t)-0.5(a)(t-squared)

## The Attempt at a Solution

A) D=(V2)(t)-0.5(a)(t-squared)
re-arranges to d+0.5(a) = t ?
V2

B) ?

i have no clue my teacher is terrible ?

first of all, don't change variables in the middle of a solution ...
your equations for v1x and v1y are okay , but what is v2 ?

what quantity do you think "D" is ? ... is "d" the same quantity?

second, you have to use proper algebra to re-arrange (to isolate t^2 ...)