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Basis Atom of Superconductor

  1. Mar 7, 2015 #1
    Hi everyone, I'm trying to simulated the XRD pattern of Bi2Sr2Ca2Cu3O10, but i'm having a problem of finding the basis of atom(and their respective position). Also its JCPDS is quite hard to find, so if anyone working with this, may you provide a link or articles about my problem.

    Thanks.

    (PS: don't forget the JCPDS.)
     
  2. jcsd
  3. Mar 7, 2015 #2
  4. Mar 7, 2015 #3
    @M quak, if you know the the basis atom and their position may you listed here? thanks.
     
    Last edited: Mar 7, 2015
  5. Mar 10, 2015 #4
    PLEAS I HOPE TO LEARN MY DREAM LEARN HOW MADE SUBSTANC ??
     
  6. Mar 11, 2015 #5
    It took me less than 5 minutes searching for "Bi2Sr2Ca2Cu3O10 crystal structure"
    http://arxiv.org/pdf/1307.4491.pdf
    If you can simulate an XRD why can't you google ?
     
  7. Mar 11, 2015 #6
    Thank you sir for your effort to resolve my problem, but i already saw that article, and i think it is an incomplete data, because it only includes z coordinates, also there is no XRD or JCPDS provided. but anyway thanks again for your concern (on your 5 minutes concern).
     
  8. Mar 11, 2015 #7

    TeethWhitener

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    The x and y information is encoded in the symmetry of the crystal (space group I4/mmm) and the lattice constants (a and c).
     
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