# Basis of row(A)

1. Mar 18, 2010

### temaire

1. The problem statement, all variables and given/known data
http://img708.imageshack.us/img708/7309/10324398.jpg [Broken]

3. The attempt at a solution
First I row reduced the matrix into the RREF and got

$$\left[ \begin{array}{cccc} 1 & 0 & -1 & -2 \\ 0 & 1 & 2 & 3 \\ 0 & 0 & 0 & 0 \end{array} \right]$$

(0,1,2,3) is a linear combinatin of (1,2,3,4) and (2,6,10,14) so you drop it. Therefore {(1,0,-1,-2), (0,1,2,3)} is a basis of row(A).

Am I correct?

Last edited by a moderator: May 4, 2017
2. Mar 18, 2010

yes.