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Basis of row(A)

  • Thread starter temaire
  • Start date
  • #1
279
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Homework Statement


http://img708.imageshack.us/img708/7309/10324398.jpg [Broken]

The Attempt at a Solution


First I row reduced the matrix into the RREF and got

[tex]
\left[ \begin{array}{cccc} 1 & 0 & -1 & -2 \\ 0 & 1 & 2 & 3 \\ 0 & 0 & 0 & 0 \end{array} \right]
[/tex]

(0,1,2,3) is a linear combinatin of (1,2,3,4) and (2,6,10,14) so you drop it. Therefore {(1,0,-1,-2), (0,1,2,3)} is a basis of row(A).

Am I correct?
 
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Answers and Replies

  • #2
105
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yes.
 

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