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Basis of row(A)

  1. Mar 18, 2010 #1
    1. The problem statement, all variables and given/known data
    http://img708.imageshack.us/img708/7309/10324398.jpg [Broken]

    3. The attempt at a solution
    First I row reduced the matrix into the RREF and got

    [tex]
    \left[ \begin{array}{cccc} 1 & 0 & -1 & -2 \\ 0 & 1 & 2 & 3 \\ 0 & 0 & 0 & 0 \end{array} \right]
    [/tex]

    (0,1,2,3) is a linear combinatin of (1,2,3,4) and (2,6,10,14) so you drop it. Therefore {(1,0,-1,-2), (0,1,2,3)} is a basis of row(A).

    Am I correct?
     
    Last edited by a moderator: May 4, 2017
  2. jcsd
  3. Mar 18, 2010 #2
    yes.
     
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