1. The problem statement, all variables and given/known data A basketball player who is 2.00 m tall is standing on the floor L = 8.0 m from the basket, as in Figure P4.54. If he shoots the ball at a 30.0° angle with the horizontal, at what initial speed must he throw so that it goes through the hoop without striking the backboard? The basket height is 3.05 m. 2. Relevant equations y=Yo+Voyt-(g/2)t squared X=Xo+Voxt-(g/2)t squared 3. The attempt at a solution Vxo=cos(30) Vyo=sin(30) Vo (cos 30)=8 3.05=2.00+Vo-4.9t squared 3.05=10-4.9t squared t=square root (6.95/4.9) =1.191 Vo=8/(.7071*1.191) =9.499 However, this is wrong...any suggesions??