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## Homework Statement

A basketball player who is 2.00 m tall is standing on the floor L = 8.0 m from the basket, as in Figure P4.54. If he shoots the ball at a 30.0° angle with the horizontal, at what initial speed must he throw so that it goes through the hoop without striking the backboard? The basket height is 3.05 m.

## Homework Equations

y=Yo+Voyt-(g/2)t squared

X=Xo+Voxt-(g/2)t squared

## The Attempt at a Solution

Vxo=cos(30)

Vyo=sin(30)

Vo (cos 30)=8

3.05=2.00+Vo-4.9t squared

3.05=10-4.9t squared

t=square root (6.95/4.9)

=1.191

Vo=8/(.7071*1.191)

=9.499

However, this is wrong...any suggesions??