(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A baton twirler throws a spinning baton directly upward. As it goes up and returns to the twirler's hand, the baton turns through four revolutions. Ignoring air resistance and assuming that the average angular speed of the baton is 1.80 rev/s, determine the height to which the center of the baton travels above the point of release.

2. Relevant equations

w=[tex]\theta[/tex]/Delta t

*v=v_{o}+at ~ w=w_{o}+[tex]\omega[/tex]t

*v^{2}=v_{o}^{2}+2ax ~ w^{2}=w_{o}^{2}+2[tex]\omega[/tex][tex]\theta[/tex]

*x=v_{o}t+(1/2)at^{2}~ [tex]\theta[/tex]=w_{o}t+(1/2)at^{2}

the ones with * means i changed it to what the problem is about. means the same thing just different letters so you wont get confused i guess.

3. The attempt at a solution

you find the height which is the same as distance but how would you plug that in? would the rev/s be the velocity part? its not in m/s are you supposed to convert it or something? i know it makes 4 revolutions but i still have no idea what to do just get the answer and multiply it by 4? please help!

thank you!

sweedel joseph

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# Baton twirler problem

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