1. The problem statement, all variables and given/known data A light bulb is rated at 3 watts when connected to a 6 volt battery. How much power will it dissipate if it is connected to a 12 volt battery? 2. Relevant equations P = IV 3. The attempt at a solution 3w = I(6v) I = 1/2 P = (1/2)(12v) P = 6w. Okay, so I heard the answer was 12w from a friend, but I got 6w. I'm not really sure about my answer.. because I guess the current really wouldn't stay the same right?