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**[SOLVED] Battery with internal resistor**

## Homework Statement

What is the current in a 8.25 ohm resistor connected to a battery that has a .21 ohm internal resistance when the potential drop across the terminals of the battery is 6V?

## Homework Equations

[tex]R_{s}=R_{1}+R_{2}...[/tex]

[tex]V=IR[/tex]

## The Attempt at a Solution

So I believe that the internal resistor can just be considered being in series to the other resistor, allowing me to calculate the equivalent resistor. Then with that, using V=IR, I thought I was able to get the current flowing through the circuit. I got .70921 A

Can someone correct my train of thought?