Baye's Rules Help

  • Thread starter wown
  • Start date
  • #1
22
0
Question:
You have 100 coins. 99 are fair and 1 is double sided. You pick a random coin and flip it 10 times and get 10 heads in a row. What is the probability that you picked the double sided coin?

Response / help needed:
Probablity of picking a 1 sided coin = .01
Probability of heads 10 times in a row with an fair coin = .5^(10)
Probability of heads 10 times in a row with an unfair coin (assuming the head is on both sides) = 1

So, i think, according to baye's, the equation should be
.01*1/ (.01*1+ .5^10*.99) = .912

Is that correct?

Also, what would you do if you do not assume heads is on both sides?
 

Answers and Replies

  • #2
D H
Staff Emeritus
Science Advisor
Insights Author
15,393
685
So, i think, according to baye's, the equation should be
.01*1/ (.01*1+ .5^10*.99) = .912

Is that correct?
Looks good!

Also, what would you do if you do not assume heads is on both sides?
You would calculate P(fair coin | 10 heads in a row), which would give the same denominator as you had but the numerator would be 0.99*0.510. Taking 1 minus this value will yield the same result you obtained.
 

Related Threads on Baye's Rules Help

  • Last Post
Replies
2
Views
2K
  • Last Post
Replies
21
Views
9K
  • Last Post
Replies
1
Views
3K
Replies
5
Views
3K
Replies
11
Views
6K
Replies
1
Views
2K
  • Last Post
Replies
5
Views
611
Replies
2
Views
1K
  • Last Post
Replies
2
Views
3K
  • Last Post
Replies
4
Views
2K
Top