A beach ball is made of thin plastic. It has been inflated with air, but the plastic is not stretched. By swimming with fins on, you manage to take the ball from the surface of a pool to the bottom. Once the ball is completely submerged, what happens to the buoyant force exerted on the beach ball as you take it deeper? Now I know that Archimedes' principal states that the buoyant force is equal to the weight of the displaced water. This is a multiple choice question and I choose that the buoyant force remains the same, and it said i was wrong. All help appreciated.