(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A bead slides without friction around a loop-the-loop. The bead is released at height y from the bottom of the loop, which has radius r. What is the instantaneous kinetic energy K at the top of the loop so that the bead would press the track with an upward force F=mg/2?

Express the height y in terms of K, m, and r.

2. Relevant equations

K=.5mv^2

cent acceleration=(v^2)/r

3. The attempt at a solution

I drew a FBD with weight mg down and F mg/2 up. The sum was mg/2 down, which I set equal to m(v^2)/r. I arranged the equation to get v^2=gr/2, and plugged that into the kinetic energy equation, getting mgr/4 as the incorrect solution.

I was able to get the second part through energy conservation, setting mgy=2mgr + K and solving.

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# Bead around a loop

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